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How many molecules of methyl alcohol, CH3OH, are contained in 2.0 x 10^-4 g of the compound?

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How many molecules of methyl alcohol, CH3OH, are contained in 2.0 x 10^-4 g of the compound?

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  1. C = 12

    H = 1

    O = 16

    CH3OH = 32 (near enough)

    2.0 x 10^-4 g contains 6.25 x 10^-6 moles =  3.764 x 10^18 molecules

    (Avogadro's number is 6.02214×10^23)  

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