Question:

How many moles of C6H12O6 are formed when 0.250 mole of CO2 is consumed in the reaction?

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reaction: 6 CO2 + 6H20 --> C6H12O6 + 6O2

I have the answer and it's 0.0417. But I REALLY NEED THE STEP BY STEP. I don't understand it at all. and it's not in my textbook as well as my notes.

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  1. Not that many steps.  You have the moles of CO2 and the reaction.   NOW...the reaction says for each 6 moles of CO2 "consumed", 1 mole of sugar is formed.  By proportion:

    0.25 moles/6 moles {CO2}= x moles/1mole {sugar}.  x is the answer.


  2. You are making this way too hard.  Suppose you were making a cake (not cupcakes!) and putting in the eggs.  If you put in six eggs, you still get only one cake so the number of cakes is 1/6 the number of eggs.  This is what the chemical equation shows you: 6 CO2 (eggs) ---> 1 C6H12O6 (cakes).  

    Keep in mind that 0.25 moles of CO2 (eggs) is still a lot of molecules of CO2.  Every group of 6 molecules of CO2 will give one molecule of glucose (one cake).  Many mole problems are just variations of this same idea.

  3. the equation states that it takes 6 moles of CO2 to make l mole of C6H12O6. (6 CO2) that mean 6 moles of CO2 to make 1 mole (there is no number in front of C6H12O6 and that means only one mole).  Therefore if you have 0.25 moles of CO2 you divide that by 6 to get the number of moles of C6H12O6. So 0.25/6 = 0.04166 moles of C6H12O6.  Try to think of this way, there are 6 times as many moles of C02 as there are C6H12O6.  You started out with 0.25 moles of CO2 so you will get ).25 /6 moles of C6H12O6

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