Question:

How many moles of Ca3(PO4)2 would be formed from 40 grams of Ca in the following (UNBALANCED) equation?

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Ca + H3PO4 → Ca3(PO4)2 + H2

I believe that the balanced equation is:

3 Ca + 2 H3PO4 → Ca3(PO4)2 + 3 H2

But I am not sure where to go from there to find the answer.....

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2 ANSWERS


  1. Convert the 3Ca to moles.  Then use the molar ratio of 3Ca to Ca3(PO4)2.


  2. Balanced equation is right

    moles of Ca = mass of calcium / Atomic Weight of Ca

    =40/40

    =1

    As 3 moles of Ca will form 1 mole of Ca3(PO4)2 (from balanced equation), 1 mole of Ca will form 1/3 of Ca3(PO4)2 or 0.33 moles

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