How many moles of H2 and N2 are present at equilibrium?

Question

1. Hydrogen and nitrogen react together at 500K to form ammonia in a reversible reaction. The equation is given below:

3H2(g) + N2(g) 2NH3(g)

a) 3 moles of H2 are mixed in a reaction vessel with 1 mole of N2 and left to come to equilibrium at 500K. At equilibrium, the number of moles of NH3 was found to be 0.3. (The volume of the reaction vessel was 2dm3).

Answer 1

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Answer 2

Reaction ration is 3: 1: 2

your 0.3 represents the "2" part, so the "1" is 0.15 and the "3" os 0.45 moles.

That's the amount that HAS reacted, so what's left at equilibrium is

for H2 (3-0.45) = 2.55 moles

for N2 (1-0.15) = 0.85 moles

and of course NH3 = 0.3 moles (which is where we started!)