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How many moles of gas are contained in 890.0 mL at 21.0 °C and 750.0 mm Hg pressure?

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How many moles of gas are contained in 890.0 mL at 21.0 °C and 750.0 mm Hg pressure?

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  1. Memorize this equation-

    PV=nRT

    P = pressure in atmospheres (1 atm = 760 mm Hg or 760 torr)

    V = volume in liters

    n = moles

    R = 0.08206 (gas constant)

    T = temperature in deg K (273.15 + deg C = deg K)

    n = PV/RT =  (750/760) atm x 0.890 L / (0.08206 x 294.25 deg K) = 0.0364 mole

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