How many seconds does it take to deposit 96.0 g Zn on a steel gate when 39.0 A is passed through a ZnSO4 solut

Question

How many seconds does it take to deposit 96.0 g Zn on a steel gate when 39.0 A is passed through a ZnSO4 solution?

Answer 1

96.0 grams of Zn @ 65.39 g/mol = 1.468 moles of Zn

since:  1 Zn+2   &  2 electrons --> 1 Zn

1.468 mol Zn  requires .... twice.... 2.936 moles of electrons

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2.936 moles of e- @ 96,485 Coulombs / mol e- = 283,302 Coulombs

since Coulombs = (amps) ( seconds)....

283302 Coulombs = (39.0 amps) (seconds)

seconds = 7264 seconds

your answer is (3sig figs) : 7,260 seconds