How much CO2 do you get after .125grams or moles of butane react with O2?

Question

How much CO2 do you get after .125grams or moles of butane react with O2?

Answer 1

2CH3CH2CH2CH3 + 13O2 --> 8CO2 + 10H2O

You first have to find out how many moles of butane (molar mass 58,12 g/mol) are contained in 0,125g: mol = mass / molar mass = 0,125 / 58,12 = 0,00215 mol.

The reaction says that 2 moles of butane give 8 moles of carbon dioxide that have a molar mass of 44,01 g/mol. Now solve the proportion 2 : 2,15 x 10^-3 = 8 : X --> X = 8,6 x 10^-3 mol.

Using the same formula we used before: mol = mass / molar mass --> 8,6 x 10^-3 = mass / 44,01 --> mass = 0,378 g of CO2 released from the reaction