How much heat is required to warm 100kg of water by 20 degrees C?

Question

How much heat is required to warm 100kg of water by 20 degrees C?

Answer 1

100kg x 4.184kJ/kg/°C x 20°C = 8,368kJ required.

(Or: 100kg x 1kcal/kg/°C x 20°C = 2,000kcal required).

(Check: 2,000kcal x 4.184kJ/kcal = 8,368kJ)

(Or: 100kg x 2.2lb/kg = 220lb.

220lb x 1Btu/lb/°F x 68°F (20°C). = 14,960Btu required)

Answer 2

2,000,000 calories

It's 1 calorie per gram, per degree C.

(1 Calorie on a food label is 1,000 of these calories.)

or

8,372 kilojoules

It's 4.186 kilojoules per kilogram, per degree C.

Answer 3

formula to get heat is

H = mass*calorific value*change in temperature

here,

mass=100kg

calorific value = 4.184kJ/kg/°C = 1kcal/kg/°C

change in temperature = 20°C

H = 00kg x 4.184kJ/kg/°C x 20°C = 8,368kJ required.

H = 100kg x 1kcal/kg/°C x 20°C = 2,000kcal required.