How much of H2SO4 and NACL is in 200L Hydrochloric acd

Question

How much of Sulphuric acid and Sodium Chloride is needed to make 200l Hydrochloric acid?

Answer 1

The balanced equation is: H2SO4 + 2NaCl = 2HCl + Na2SO4

The ratio of H2SO4 to NaCl to HCl from the equation is 1:2:2

The weight of HCl is (H = 1, Cl = 35) 36 grams per mole. Given 200 L, divide this by the weight of 1 mole of HCl = 5.6 moles. Using the ratio, you would have (in moles) 2.78: 5.56: 5.56.  In grams you need the weight of H2SO4.

H = 2 x 1 = 2 grams

S = 32 grams

O = 16 x 4 = 64 grams

Together they total 98 grams x 2.78 moles = 272 grams per mole

Grams of NaCl:

Na = 23 grams

Cl = 35 grams

Together they total 58 grams x 5.56 moles = 322.5 grams per mole

Grams of HCl:

H = 1gram

Cl = 35 grams

Together they total 36 grams x 5.56 = 200 grams per mole

Answer 2

H2 SO4 + 2Na Cl--------------------> Na2 SO4 + 2HCl

                                                                  200lt of HCl

                                                                      

4.45 moles of H2SO4   8.9 moles of NaCl                                8.9 moles of HCl

thus 436.1 gms of H2 SO4 and 502.8 gms of NaCl are required