Question:

How much of the absorption in the spectrum below is from nitrogen?

by  |  earlier

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The source is

http://webbook.nist.gov/cgi/cbook.cgi?ID=C124389&Units=SI&Type=IR-SPEC&Index=1#IR-SPEC

The easiest viewed spectrum is

http://webbook.nist.gov/cgi/cbook.cgi/124-38-9-IR.svg?Spec=C124389&Index=1&Type=IR&Large=on&SVG=on

The sample is 1/3 CO2, 2/3 N2.

Note that the raw data is also provided in JCAMP format, which is a standard format for exchanging spectroscopic data. The file consists of a header and a data section. The transmittance values can be read directly from the DATA section. The first column is a wavenumber reference for the first transmittance value in the row. Note that the transmittance spectrum should be converted to an absorbance spectrum A = -log(T) to calculate the molar extinction.

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2 ANSWERS


  1. aaargh! i'm just going to guess on the middle one, because nitrogen is in between carbon and oxygen in the periodic table, say a 1/0 bigger than other big dip, -logT so about 90%?

    i just know i got that wrong. even more respect to those scientists doing all this work for us.

    bother, i knew i hadnt read the question properly. doh! should have kept quiet.


  2. Nitrogen is not a green house gas and doesn't absorb IR.  If I understand the question, the answer is zero.  The website didn't work well so I made an assumption.

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