Question:

How much would you weigh if...?

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Let's say it's the spring or fall solstice. Earth's axis is perpendicular to its orbit around the sun. So, you go to the north pole (true, not magnetic) and weigh yourself. You then immediately teleport yourself to the equator. How much less would you weigh at the equator where earth's centrifugal force would be the greatest?

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  1. I don't have numbers to quote, but remember you also will weigh less due to being further from the center of the earth.  Even with both causes adding together I don't think the difference would be much, but measurable.


  2. All da same to me, man

  3. if you remember, weight is a force, and is the product of mass and acceleration.  Now, with respect to the centrifugal force applied on the person:  Yes, you are significantly closer to the axis, but the speed of rotation is so slow that the increase in acceleration on your body would be too small to make any significant difference.  The acceleration due to gravity would be the same since gravity is a property that deals with the mass of things.  So, you would weigh the same anywhere on this planet.

  4. Did I have a snack on the way to the equator.

  5. Including non-spherical gravity, the effective gravity of Earth is about 0,43% less at the equator, compared to the poles.  

  6. That's a good question.  I don't have the math skillz to work it out, but at the equator you're traveling in a circle the diameter of the earth at about 1000 MPH.  So you're losing some weight due to centrifugal force, but I'm not sure what it works out to.  It wouldn't be much less, though.

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