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How to antidifferentiate (sinx)^2 and (1-cosx)^2 ??

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  1. sin²x = 1 - cos²x = 1 - (1/2)(cos(2x) +1)

    = 1 - (1/2)cos(2x) - 1/2

    = 1/2 - (1/2)cos(2x)

    Now integrate.

    1/2x - (1/4)sin(2x) + C

    You'll use the same identity: cos²x = (1/2)(cos(2x) +1) for the second one.

    Remember to expand (1-cosx)² first.

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