How to calculate the distance of a point from a plane (3d)?

Question

I need to calculate the distance of a point from a plane, but i don't know the method for doing so, and Googling isn't helping me. >_>

As i need the method i have changed the variables so it doesn't matter if these numbers are used in your answers or others numbers, these are just to show what i mean:-

Calculate the distance of the point (2,-2,10) from the plane 6x+8y-z=28

Answer 1

What you need to do, right... What you need to do mate, is put a donk on it! Whaaa!

Answer 2

Suppose the equation of the plane is

ax + by + cz + d = 0

and the point is (x1, y1, z1)

then

the distance = (|ax1 + by1 + cz1 + d|)/sqrt(a^2 + b^2 + c^2)

In the given problem,

equation of plane is 6x+8y-z=28

i.e. 6x+8y-z-28 = 0

a = 6, b = 8, c = -1, d = -28

x1 = 2, y1 = -2, z1 = 10

Substitute the values.