Question:

How to convert the following into Joule:a) 1 kg of steamb) 1 kWh of electricityc) 1 cu.m of natural gas?

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Can you provide the detail conversion factor? From where the factors was derived.

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  1. for a and c; you're lacking data, mate. We're gonna need thermodynamical properties of the steam and gas before you can know how much energy (in joules) the steam and gas carries.

    for b) 1 kWh * 3600 (h/ sec) = 3600 Joules


  2. Watch the k mate..

    For b) 1 kWh = 1000 * 1 * 3600 = 3.6 ^6 joules

    For c) conditions are assumed to be for a normal cu m, ie 760 mm Hg and 0 deg C.  Since 1 kg-mole occupies 22.4 cu m under normal conditions, 1 cu m will contain 44.64 g-mole of what we assume is pure methane.  Heat of combustion of methane is 212.8 kcal/g-mol.

    So, h = 212.8 * 44.64 = 9500 kcal  * 4187 J/kcal

                                          = 39.8 ^6 J

    For c) you are looking for the heat content of the steam compared to some reference state of condensation.  You have to know the steam pressure and temperature, and the reference state which might for instance be the operating temperature of a steam surface condenser.  The heat content of the steam is then just the difference in enthalpy between the steam and the condensate.  Use your steam tables.

  3. one joule equals one newton-meter

    one joule per second equal one Watt

    check out the following link http://www.gasairconditioning.org/gas_co...

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