How to deduct coefficient of friction?

Question

I am trying to find the applied force but i dont know how with a coefficient of friction.

D=60m

M=50kg

W=2.2 x 10^3 J

constent speed

coefficient of friction = 0.26

What is the force applied?

What is the angle?

Answer 1

W= F.d

2200/60=Force=36 2/3 N

    Ff = μFn

where

    * Ff is either the force exerted by friction, or, in the case of equality, the maximum possible magnitude of this force.

    * μ is the coefficient of friction, which is an empirical property of the contacting materials,

    * Fn is the normal force exerted between the surfaces

therefore force applied is (36 2/3 N)/0.74=49.55N

this is only true for a pure horizontal direction (0 degree).

for different angle, you need to times force applied with cos(angle) because friction only applied to forces normal to the contact surface, and then divided by 0.74 you'll get a horizontal force. To get a vertical force, just use 36 2/3 x sin(angle).