How to determine the total resistance in series connection?in parallel connection?

Question

pls help!

Answer 1

In Series Connection the total resistance equals to the some of all resistances as the current the same constant for all resistances and Potential difference is divided

R (total) = R (1) + R (2) + R (3)

In parallel Connection the current is divided and the the potential difference is the same

1/ R (total) = 1/ R (1) + 1/ R (2) + 1/ R (3)

Answer 2

in series.. R=r1+r2+r3+...

in parallel..1/R=1/r1+1/r2+..

Answer 3

I assume ur refering to resistors in series and parallel. Resistor in series add up. ie if r1 = 1 ohm and r2 = 2 ohm the rt in series = r1 + r2 = 3 ohms. formula rt = r1+ r2 +...rn

Resistances in parallel are a little trickier, you add the inverse of each value and inverse that value. for the above values in paralled it would be 1/(1/r1 + 1/r2) = 0.667 ohms

formul rt = 1 /(1/r1 + 1/r2 +... 1/rn)

Answer 4

in series  R = R1+R2+R3+......

in parallel 1/R= 1/R1+1/R2+1/R3+.........

explanation

SERIES

basic equation  V= IR

total voltage=sum of individual voltages across resistors

V = V1+V2+V3

IR= I1R1+I2R2+I3R3

   R  = R1+R2+R3   since current is same

PARALLEL

basic equation  V= IR

total current=sum of individual currents through resistors

I = I1+I2+I3

V/R = V1/R1+V2/R2+V3/R3

1/R = 1/R1+1/R2+1/R3   since voltage is same

Answer 5

Series - add.

Parallel : 1/R = 1/r1 + 1/r2 + 1/r3 ....