How to do this weird maths question?

Question

Given that 0° £ x £ 180°, find the possible value(s) of x if sin x = 0.707

I'm stumped on this one. Probably because I have no clue what this is. If this is a bearings question, someone help me out please.

Answer 1

I think the (English Currency Symbol) is intended to be

either < or <= (less than or less than-or-equal to).

0.707 is an approximation for our old friend sqrt(2)/2

So in the range 0 through 180°, the value of the sin function

being equal to sqrt(2)/2 happens twice:

at 45° and 135°.

Answer 2

I am assuming the problem is asking to find the values of sinx on the interval 0<x<180.  sinx= .707 is 45 degrees or pi/4.  This would mean that it is also equal to 3pi/4  on the interval 0<x<180.

Answer 3

I assume you mean 0° <= 180°.

sin x = 1/sqrt 2 for x = 45 degrees and 135 degrees.