Question:

How to evaluate limits of sin?

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HELP with details please

ty

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  1. Greetings,

    lim  sin(5x)/3x =

    x->0

    multiply and divide by 5/5

    lim (5/3)sin(5x)/(5x) =

    x->0

    5x -> 0 as x -> 0

    (5/3)(lim5x->0 sin(5x)/5x) =

    (5/3)*(1) =

    5/3

    Regards


  2. sin(X)= X when X->0

    sin(5X)=5X when X->0

    So then answer= 5X / 3X = 5/3
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