How to factor this problem?

Question

81w^2-180wt+100t^2

Answer 1

Express in the form a^2 - 2ab + b^2 to get (a - b)^2 formula.

81w^2 - 180wt + 100t^2

= (9w)^2 - (2*9w*10t) + (10t)^2

= (9w - 10t)^2

= (9w - 10t)(9w - 10t)

This is also the same as.

(10t - 9w)(10t - 9w)

because (a - b)^2 = (b - a)^2

Answer 2

81 w^2 = 9w (9w) or (-9w)(-9w)

100t^2 = 10t (10t) or (-10t) (-10t)

the center is =  -180wt

we should take the (-) sign

(9w-10t) (9w-10t)  

Answer 3

81w^2 - 180wt + 100t^2

= 81w^2 - 90wt - 90wt + 100t^2

= (81w^2 - 90wt) - (90wt - 100t^2)

= 9w(9w - 10t) - 10t(9w - 10t)

= (9w - 10t)(9w - 10t)

= (9w - 10t)^2

Answer 4

81w^2-180wt+100t^2

(9w)^2-2 x 9w x 10t+(10t)^2

=(9w-10t)^2  [by using the formula (a+b)^2=a^2+b^2-2ab]

:))

Answer 5

Look at the outside terms, do you see a root in the multipliers?

81= 9 x 9

100 = 10 x 10

so (9w-10t)(9w-10t)

81 w^2  - 90wt -90wt + 100t^2

81 w^2 -180wt + 100t^2