How to find acceleration.?

Question

An object moving with constant acceleration has velocity v = 49.9 m/s when it is at x = 8.6 m and v = 84.5 m/s when it is at x = 15.1 m. What is its acceleration?

I tried doing (84.5 m/s - 49.9 m/s) / (15.1m -8.6 m) and got 5.32, but apparently that is incorrect. Any help?

Answer 1

S1=8.6m,V1=49.9m/s.S2=15.1m,V2=84.5m/s,a...

   V^2=U^2+2as write this formular for two then compare an cut the one u not using(u^2)  V^2=2as

    49.9^2=2*a*8.6  = (a)1=2490.01/17.2  = (a)1=144.77m/s^2

    84.5^2=2*a*15.1 = (a)2=7140.25/30.2 =(a)2=236.43m/s^2

therefore accleration is the difference i think 91.66m/s^2(if I am wrong tell me the answer).

  

Answer 2

The correct formula is

v2²  - v1² = 2a(x2 - x1)  

Answer 3

one problem with your answer is that you have velocity divided by distance (i.e. meters/sec divided by meters)  Acceleration is m/(s*s)

Do you have any other info in the problem?