How to find equivalent weight of KMnO4?

Question

i want to know that how to find equivqlent wt of a oxidizing or redusing agent.plz mail me.

Answer 1

KMnO4 has a Molar mass of 158.04 g/mol

to find its equivalent weight as an oxidizer we need to divide the Molar mass by the moles of electrons taken in its half reaction

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the less common half reaction, uses KMnO4 as an oxidizer in an basic solution:

KMnO4  (takes 3 electrons)  & OH- --> MnO2 (s)

in which case your answer comes form:

158.04 g/mol divided by  3 moles of e- =

Your less commonly used answer = 52.68 grams / equivalent

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the most common half reaction, uses KMnO4 as an oxidizer in an acidic solution:

KMnO4  (takes 5 electrons)  & 8 H+ --> Mn+2

in which case your answer comes form:

158.04 g/mol divided by 5 moles of e- =

Your most widely used answer = 31.61 grams / equivalent