How to find molarity in a percent solution?

Question

Here's the question: The mass of hydrogen is 1.0, carbon 12.0, oxygen 16.0 & the chemical formula for glucose is C6H1206. What is the molarity of a 10% glucose solution?

Can someone help me answer this question pleeeasse? :)

Answer 1

A 10% solution is one where the mass of the solute dissolved in the solution is equal to 10% of the volume of the solution

So 10% w/v C6H12O6 = 10 g / 100 ml of solution

Molarity = moles / litres

moles = mass / molar mass

molar mass C6H12O6 = (6 x 12.0) + (12 x 1.0) + (6 x 16.0) = 180.0 g/l

therefore moles sucrose = 10g / 180.0 g/mol

= 0.05556 moles of C6H12O6

This is in 100 ml (0.10 L) of solution

So M = moles / L

= 0.05556 mol / 0.10 L

= 0.556 M

Answer 2

we can consider (w/v) %

Let the volume of solution be 100 mL

mass of glucose (solute) = 10 g

no. of moles = 10/180

                       = 1/18

Molarity = n/V

              =1*1000/18*100

              = 0.56 M