Question:

How to find the base of a triangle?

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How do I find the base of a triangle if i am given the area (48 sq. inches) and the height which is 16 inches?

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15 ANSWERS


  1. The formula for area is:

    A = 0.5 x b x h (half times base times height)

    so you know 48 = 0.5 x 16 x h

    48 = 8 x h

    h = 48/8 = 6 inches


  2. The area of a triangle is given by the formula

    Area = A = (1/2)bh

    where

    b = base

    h = height

    Substituting values,

    48 = (1/2)(b)(16)

    and solving for "b",

    b = 2(48)/16

    b = 6 inches

      

  3. ?x16=48?

    3.

    So 3 is half the base.

    3x2=6

    So the base is 6


  4. to find the area you multiply the base X height and then devide by two... so in your case multiply the area x2 and then divide by the height.  96/16 = 6... your base is 6

  5. A = 1/2bh

    Therefore:

    48 = 1/2(b)(16)

    48/16 = 1/2b

    48/16/.5 = b

    b = 6

    To test:

    1/2(6)(16) = 48

    Correct.

  6. Area of triangle= half base times height so..

    Base= Area divided by height(3) times 2 which equals 6

    answer= 6  

  7. area = 1/2 of the base times the height

    A= 1/2 bh

    so...48=16b(.5)

    16b=96

    b=6


  8. Look at the bottom of the triangle, it's there.

  9. a = bh/2

    2a = bh

    b = 2a/h

    (base = 2 * area/height)

    2 x 48/16

    = 96/16

    = 6 inches


  10. area = base times heigt divided by 2

    48 = (b * 16)/2

    b = 6

  11. area = (base x height) / 2

    48 = 16b / 2

    96 = 16b

    6 = b

  12. i got a C in geometry this year so i cannot help you. geometry is the worst class ive ever taken

    sorry =(

  13. 1/2base times height = area

    1/2b*16 = 48

    1/2b = 3

    b = 6 inches


  14. turn around

  15. area = ½ base • height

    48 = ½B(16)

    48 = 8B

    B = 6 in.

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