How to print the foll. in C?

Question

*

* *

* * *

* * * *.....as many times we want?

Answer 1

include<stdio.h>

#include<conio.h>

void main()

{

int i,j,n;

clrscr();

printf("how many lines do u want");

scanf("%d",&n)

for(i=0;i<n;i++)

{

  for(j=0;j<=i;j++)

  {

   printf("*");

  }

printf("\n");

}

getch();

}

Answer 2

Even though these questions are fun to do, I hate actually giving out the answer because I always feel like I'm doing someone else's homework for them. This code is mine, and I only grant you permission to use it under the condition that you sincerely attempt to understand it, because otherwise I don't want to have you as my coworker 10 years from now.

#include <stdio.h>

#define STOP_VAL 25

/*

* This is a recursive function. Think about why I implemented it this way.

* Each level of your "asterisk tree" can be defined by the previous level.

* e.g. the number of stars in level 5 is the number of stars in level 4 + 1,

* and so on until you arbitrarily decide to stop. If I didn't have the

* line marked below in there, this would be an infinite loop.

*/

void printfunc(int num_times) {

        int i;

        if (num_times == STOP_VAL) return; /* this one */

        for(i=0; i< num_times; i++) {

                printf("*");

        }

        printf("\n");

        printfunc(num_times + 1);

}

/* ..and of course all good C programs have a function of this signature */

int main(int argc, char *argv[]) {

        printfunc(1);

}

Answer 3

coding for project-

http://codingforum.info/    

Answer 4

main()

{

int i=0;

int n=0,t=0,k=0,s=0,j=0;

clrscr();

printf("Enter N ");

scanf("%d",&n);

t=n;

for(i=1;i<=n;i++)

{ s++;

for(j=1;j<=t;j++)

printf(" ");

for(k=1;k<=s;k++)

    printf(" *");

    printf("\n");

    t--;

}

}