Question:

How to solve this? x³+3x²-4x=0?

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How to solve this? x³+3x²-4x=0?

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  1. x(x^2+3x-4)=0

    x(x+4)(x-1)=0

    x=0 or -4  or 1


  2. x (x² + 3x - 4) = 0

    x (x + 4)(x - 1) = 0

    now u need to state the zero property otherwise it doesnt make sense

    either x=0 or x+4=0 or x-1=0

    so x=0 or x=-4 or x=+1

  3. x (x² + 3x - 4) = 0

    x (x + 4)(x - 1) = 0

    x = 0 , x = - 4 , x = 1

  4. first. factor out an X to get a quadratic equation and factor.

    x(x-1)(x+4) = 0

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