How will I produce 414mV from 1.5 V supply ?

Question

use of resistor or variable resistor here

Answer 1

Use two resistors, perhaps?

I am always suspicious when someone asks for a voltage with that level of precision. If you really need it that precise, you may need to use an op-amp and a reference voltage to obtain the value.

If the 1.5v comes from a battery, it's accuracy may be less than perfect (as it discharges).

Answer 2

Assuming that you can apply a non-varying voltage to a resistive divider, the ratios will be affected by how much current you need.  

If the current is not a fixed figure then a resistive divider is useless anyway.  

Answer 3

Use a transformer.

Answer 4

You need to split 1.5V in the ratio of 0.414 / 1.5

You will need to put two resistor in series across the 1.5 V supply, with the junction between the two resistors giving you the 0.414V out you want.

So 1.5V - 0.414 V = 1.086V

That means the top resistor has to drop 1.086V and the bottom one 0.414V. This is known as a potential divider network and any two resistors will work, as long as their ratio (R top / R bottom)

= 1.086 / 0.414

I hope this helps?

Answer 5

Assumption 1, this is a battery, and the voltage out of it can vary from 1.4 to 1.6 volts.

Assumption 2, you need very little current out of the 0.414 volts, as this is too low to power anything, and also too precise.

Assumption 3, you need the 0.414 volts to be stable to 0.001 volts.

Answer, you can't, easily.

A resistor divider will be too inaccurate.

Best I can do is a forward biased diode, which gets you about 0.6 volts, and then a resistor divider. But this will vary about 2 mV per degree C

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Answer 6

Try using a precision 1V reference. This is a very precise zener diode with which you will use with a series current limiting resistor.   Once you have a 1 volt reference it is easy to add a voltage divider to the 1 volt reference and obtain any voltage you need between 0 and 1 volt.

You should be able to find this and other voltage references at www.digikey.com for less than $2.

EDIT: By using a 1 volt reference followed by the voltage divider you will avoid the issue of decaying battery voltage effecting the voltage