How would I combine and simplify?

Question

(a-b / dc) (8c / bd) ??? Thanks for any help!

Answer 1

[(a-b) / dc] (8c / bd)

=[(a-b) / d] (8 / bd)

= 8(a-b) / bd^2

Answer 2

I get (8a-8b)/bd^2. 'c' does cancel out.

Answer 3

[8c(a-b)] / bcd^2  <--- only d is squared

cancel c in numerator and denominator so:

(8a - 8b) / bd^2  <--- only d is squared

Answer 4

4 ( a - b ) / c