How would I go about dividing this? College Algebra?

Question

(x^2+10x+21) / (x+7)

Answer 1

Actually forget what i said a minute ago, this is how it would be done:

(x^2+10x+21)/(x+7)

((x+3)  (x+7))/(x+7)

x+3

so the answer is x+3

hope this helps, and the long division is still a way of doing it and you get the same answer.

Answer 2

(x^2+10x+21)/(x+7)=[(x+7)(x+3)]/(x+7)=x+...

Answer 3

this isn't really college algebra at all, and the top person's right.  

Answer 4

(x² + 10x + 21) / (x + 7)

(x + 7)(x + 3) / (x + 7)  [factor x² + 10x + 21]

Answer: (x + 3)

Answer 5

(x^2+10x+21) / (x+7)

If you divide (x^2+10x+21) by (x+7) you get (x+3).

(you gotta 'see' that 7+3=10 and that 7*3=21)

To check it, multiply (x+7) and  (x+3) together: (Ignore the dots (·))

· · · ·x + 7  ---> First multiple x+7 by 3 to get 3x + 21

· · · ·x + 3 ----> Then multiply x+7 by x to get x² + 7x

· · · ·-------

· · · ·3x + 21

x² + 7x

---------------

x² + 10x +21  --->Then add 'em up.  

Answer 6

college algebra...?

I learned this back in highschool. algebra 2.

yeah, factor then NOT CANCEL, (x+7) should simplify to one with one of the factors in the numerator.

Answer 7

factor out the top so its (x+3)(x+7) then cancel out the (x+7)'s

Answer 8

i wish collage algebra was like that, i would've got a scholarship long ago! the top answer is right

Answer 9

well, the top is just quadratics. so solve that first, then the rest will be easy :D.