How would I set up this problem?

Question

The expression 16f^2 models the distance in feet that an object falls during t seconds after being dropped. Find the distance an object falls during each time.

a. 0.25 seconds

b. 10 seconds

How would I go about this setting it up? Thanks

Answer 1

so...you have this equation:

16f^2=t

right?

If so, then you would have to turn it around to get the solution.

you'd get this:

t = 16×f^2

*square root of entire equation*

sqrt(t) = 4×f

4×sqrt(t) = f

Now just fill in 0.25 and 10 for t, done.

If you want the solutions too:

4×sqrt(0.25)=f

4×0.5=f

f=2

4×sqrt(10)=f

f=4sqrt(10)  

( f=12.64911064 )

Answer 2

d= distance

t= time

you take the 16.2 inches and convert it to only inches because it would be easier.

so...

16.2 inches would = 194 inches

so problem A =

d= 194 / .25

d= 776...(thats in inches, conver to ft.)

d = 64.6 repeating.

Problem B

d=194/.10

d=1940...(thats in inches. convert to ft.)

d= 161. 6 ft.

Answer 3

Your expression does not contain t, so it is not solvable right now.  Try resubmitting it -- check that you copied it correctly