How would do i solve this quadratic inequality?

Question

x^2(squared) + 4x + 4 greater than/equal to 9

Answer 1

First make it be ≥ 0 by adding -9 to both sides: x^2 + 4x - 5 ≥ 0

Then reverse FOIL: (x + 5)(x - 1) ≥ 0

To be ≥ 0, it must be 0 or positive meaning the two factors either come out 0 (x = 1 or -5) , or both positive (happens if x > 1) or both negative (x < -5).

So answer is x ≥ 1 or x ≤ -5

(-∞, -5] U [1, +∞)

Answer 2

move the 9 over to the other side of the equation, subtract it from 4, set inequality equal to zero and factor

so you should get

X(sqd) + 4x - 5 > 0

then when you factor you should get

(x+5)(x-1)

so x= -5 and 1