How would i do 3(x+6)(x-2)?

Question

I'm not looking to cheat i need verification.

would this equal 3x^2 + 12x - 36?

because (x+6)(x+2) equals x^2 + 4x - 12

so it thought i just multiply all of that by 3?

or is that wrong?

Answer 1

you are absolutely correct

Answer 2

3(x + 6)(x - 2)

= 3(x*x + 6*x - x*2 - 6*2)

= 3(x^2 + 6x - 2x - 12)

= 3(x^2 + 4x - 12)

= 3*x^2 + 3*4x - 3*12

= 3x^2 + 12x - 36

Answer 3

Remember the order of operations.

3(x+6)(x-2) =

First, expand what's in the parentheses.

3(x+6)(x-2) =

3[x(x) + x(-2) + 6(x) + 6(-2)] =

3[x^2 - 2x + 6x - 12] =

3(x^2 + 4x - 12) =

Distribute the 3.

3(x^2 + 4x - 12) =

3(x^2) + 3(4x) - 3(12) =

3x^2 + 12x - 36

You are correct. :)

Answer 4

(x+6)(x-2) is equal to x^2 + 4x - 12.

You're right, you can multiply them all by 3 to get 3x^2 + 12x - 36 so the total factor will be

3(x+6)(x-2)

Answer 5

You are right.

You just reversed the sign in (x+2)

It should be (x - 2) just like you have it in the title.