How would i solve the following algebra problems?

Question

2z(z-8)

-7y(y2-3y)

(2r-5) (3r)

Answer 1

2z^2 - 16z

-7y^3 + 21y^2

6r^2 - 15r

Answer 2

OK, parentheses mean you multiply. So, here's what you do:

2z(z-8)

Multiply 2z by z and you get 2z squared (sorry I don't know how to do exponents on here)

Then multiply 2z by -8 and you get -16z

2zsquared multiplied by -16z is -32z to the third.

Hope I helped!