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How would u find the critical angle of a core-cladding index combination????

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umm the problem is ....

n core = 1.57, n cladding = 1.42

how would i do this??

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  1. Theta(crit.) = sine-1 [(n(clad)/n(core)]

    Theta(crit.) = sine-1 [1.42 / 1.57 ] = 64.75 degrees

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