How would you do these using powers?

Question

(2a5)3

(-3xy3)4

(5a3b4)2

(-mn8)3

(-2x2y)3 * (5xy3)2

Answer 1

a bit of ambiguity.... I'll try to interpret

for the future, if you can't do x², use x^2

(2a⁵)³ = 8a¹⁵

(-3xy³)⁴ = 81x⁴y¹²

(5a³b⁴)² = 25a⁶b⁸

(-mn⁸)³ = -m³n²⁴

(-2x²y)³ * (5xy³)² = -8x⁶y³ * 25x²y⁵ = -200x⁸y⁸

Answer 2

I'll get you started.  I'm going to retype some of your problems to remove ambiguity.

the first one  (2a^5)^3 which is 2^3 (or 8) times a^15  So the answer is 8a^15

the last part of the last one (5xy^3)^2  comes out

25 x^2 y^6