How would you figure out an absolute value equation that had an integer on the outside of the equation?

Question

such as the 3 on this equation 3|x+6|=36. Would you divide it or multiply it? or something else?

Answer 1

Divide both sides of the equal sign by 3... then you end up with |x+6|=12.  Then, you would figure out the following:

x+6=12

x+6=-12

Answer 2

Solve two equations in absolute value:

3x+18=-36

3x=-36-18

3x=-54

x=-54/3

x=-18

3x+18=36

3x=36-18

3x=18

x=18/3

x=6

x= - 18, +6

Answer 3

divide by 3.     Then

X+6=12

Now subtract 6.  

X=6

Everyone else is just plain stupid

Answer 4

first, divide both sides by the three, to get the absolute value by itself. then, treat it like any other absolute value equation. so,

3lx+6l=36

lx+6l=12

x+6=12

x=6

x+6=-12

x=-18

hope this helps.

Answer 5

36/3=12

[x+6]=12

[6+6]=12

[12]=12