How would you figure out this algebra question?

Question

I'm taking a Math Placement test for junior high. And I forgot the steps to figuring out this problem. Here it is: 4/5x + 3/10 = 9/10

By the way x is the variable. Please tell me step by step and please give me the answer. It's just a sample problem.

Answer 1

I'm going to assume the first term is (4/5)*x and not 4/(5x)

First, multiply all terms by 10 to get rid of the fractions.

10*(4/5)*x+10*(3/10)=10*(9/10)

Remember, 10*(4/5) is 8.  The other fractions the 10's on the bottom cancel out with the 10 we mulitplied by

8x+3=9

Subtract 3 from both sides

8x=6

Divide both sides by 8

x=6/8

Write your answer in lowest terms

x=3/4

If, on the other hand, it really is 4/(5x), here's the other solution:

4/(5x)+3/10=9/10

Subtract 3/10 from both sides

4/(5x)=9/10-3/10

4/(5x)=6/10

Cross multiply.  Take the top of the left times the bottom of the right and set it equal to the bottom of the left times the top of the right.

4*10=6*5x

40=30x

x=40/30

x=4/3

_/

Answer 2

Wow, I just finished algebra 1 in 9th gr. Im pretty sure you have to get the x by itself. Thats what I think. Been awhile since ive done that stuff.

Answer 3

x= 3/4