How would you simplify the log expression?

Question

e^(1+lnx)

Answer 1

e^(1+ln[x])

= e^1 * e^ln(x)

= x * e^1

Answer 2

1)Split this up using your rules of indices:

    (ie)  a^b +c = a^b * a^c

When multiplying two terms with the same base we ADD the powers.So the converse is true when we see a function with added powers,it was initially two functions of the same base multiplied.

2) e^(1+lnx) =  e^1 * e^lnx

3) ln cancels e leaving x only so:

    e^1+lnx  = xe^1

Good Luck.

Answer 3

y = e^(1 + ln x)

ln y = 1 + ln x

ln y - ln x = 1

ln (y / x) = 1

y / x = e

y = e x