How would you solve this math problem?

Question

2^(x-3) = 1/32

How about this problem?

9^x = 27^(2-2x)

Whatever is in ( ) is part of the exponent.

Thanks!

Online tutorials and guides are a big bonus!

Thanks for the help.

Answer 1

2^(x-3) = 1/32

2^(x-3) =

1/32 = 1/(2^5) = 2^-5

so 2^(x-3) = 2^-5

equatign bases

x-3 = -5 so x=-2

9^x = 27^(2-2x)

27 = 3^3 and 9 = 3^2

9^x = 3^3^(2-2x)

3^2^x = 3^6-6x

eequating bases

2x = 6-6x

8x = 6

x = 6/8

x = 3/4

go to purplemath.com and find a tutorial changing bases or soemthing.

Answer 2

See the link below for help with negative exponents.

By the way, the first answer above is incorrect, since x has to be a negative number.  Whoops.

Check your work. x = -2