Question:

I'll admit I'm lost. Sequences?

by  |  earlier

0 LIKES UnLike

I need to find the indicated term of sequence.

a(sub)n=2^n/n! I know that my first answer couldn't be right. There must be a way to simplify the terms and get a reasonable answer.

Thank you.

 Tags:

   Report

1 ANSWERS


  1. I think what you mean by a(sub)n is An, where n can be 1,2,3,4,... and the sequence you are looking for is A1, A2, A3, A4 etc. where the value of each An can be calculated by 2^n / n!

    n! = factorial(n)

    1! = 1

    2! = 2*1 = 2

    3! = 3*2*1 = 6

    4! = 4*3*2*1 = 24 and so on

    So A1 = 2^1 / 1! = 2 / 1 = 2

    A2 = 2^2 / 2! = 4 / 2 = 2

    A3 = 2^3 / 3! = 8 / 6 = 1.33

    A4 = 2^4 / 4! = 16 / 24 = 0.67

    and so on. Is it clear now? If not, drop me a note. Good luck!

Question Stats

Latest activity: earlier.
This question has 1 answers.

BECOME A GUIDE

Share your knowledge and help people by answering questions.
Unanswered Questions