I'm having a hard time with this math problem. Can someone explain it?

Question

A rectangular room is 1.4 times as long as it is wide, and its perimeter is 26 meters. Find the dimension of the room. Explain how you got it.

Answer 1

Let the width be 'x'. Then the length will be 1.4*x (* means multiply).  Now the perimeter of a rectangle is 2*(length+width). So we'll get an equation i.e. 26=2*(1.4x+x). By solving this equation you will get the length=7.6mts. & width=5.4mts. I hope that it will help u.

Answer 2

Perimeter is a sum of all the sides of the rectangle

That means, Length + Length + Width + Width

Or 2 times Length + 2 times Width

According to your question:

Length = 1.4 times Width

So, put this into your equation for perimeter

Length + Length + Width + Width = Perimeter

1.4*Width + 1.4*Width+Width+Width  = Perimeter

4.8*width = 26

Width = 26 / 4.8

Width = 5.417 metres

Length = 1.4 times Width

Length = 1.4 times 5.417

Length = 7.583 metres

Voila!

Answer 3

let X = width of rectangle

Perimenter = 2*Length + 2* Width

                 = 2(1.4X) + 2X = 26

Solve for X

Answer 4

L=length

W=width

26 = 2L + 2W

1.4L=W

26 = 2L + 2(1.4L)

26 = 2L + 2.8L

26 = 4.8L

5.412 = L

1.4L = W

1.4(5.4) = W

W = 7.56

L = 5.41

Answer 5

L=length

W=width

P=perimeter

L=1.4W

P=2L+2W

26=2(1.4W)+2W

13=2.4W

W=65/12m

L=91/12m