I'm playing a game with 6 pegs on a 7 hole board and need a solution.?

Question

The board is straight and has 7 holes in it. There are 6 pegs,3 red and 3 blue. I need to get the blue pegs on the red side and vice versa. the pegs can only jump pegs of the other color. Help?

Answer 1

Ok, the pegs will be numbered by the hole it's in and the color of it. (R=red, B=blue)

The holes are numbered 1-7, with 1 the number for the first hole and 7 as the number for the last hole.

If a hole on the board doesn't have a peg in it, I will only put the number of that hole.

The board I type out will show where the pegs are. It does not show where one peg ends up. So, all you have is make the board look like the one I typed out (within the game rules, of course.)

So here's the board:

1B  2B  3B  4     5R  6R  7R

1B  2B  3B  4R  5     6R  7R

1B  2B  3     4R  5B  6R  7R

1B  2     3B  4R  5B  6R  7R

1B  2R  3B  4     5B  6R  7R

1B  2R  3B  4R  5B  6     7R

1B  2R  3B  4R  5B  6R  7

1B  2R  3B  4R  5     6R  7B

1B  2R  3     4R  5B  6R  7B

1     2R  3B  4R  5B  6R  7B

1R  2     3B  4R  5B  6R  7B

1R  2R  3B  4     5B  6R  7B

1R  2R  3B  4R  5B  6     7B

1R  2R  3B  4R  5     6B  7B

1R  2R  3     4R  5B  6B  7B

1R  2R  3R  4     5B  6B  7B

That's pretty much it.

(There's another method, which is pretty much the opposite of this one.)