I Need Chemistry Help!!!!!!!!?

Question

Im stuck on this one question for a chem summer packet. help plz

The German chemist Fritz Haber proposed paying off the reparations imposed against Germany after World War I by extracting gold from seawater. Given that (a) the amount of the reparations was 28.8 billion dollars, (b) the value of gold at the time was about $21.25 per troy ounce (12 troy ounces = 1 lb), and (c) gold occurs in seawater to the extent of 4.67 x 1017 atoms per ton of seawater (1 ton = 2000 lb), how

many cubic kilometers of seawater would have had to be processed to obtain the required amount of gold? Assume that the density of seawater is 1.03 g/cm3.

thanks in advance

Answer 1

The key here is the atomic mass of gold.  6.022X10^23 atoms of gold has a weight of 196.97 g.  There are 454 g in a lb.  Really, that's all the information you'll need to solve this problem, the rest is just converting some units (like cm^3 to km^3), multiplication and division.