I am having trouble with this math problem. Its College Algebra?

Question

Simply as far as possible... Please explain how to do it as well

((256x^7)(y^13)(z^16))^1/4

Answer 1

Seek and you shall find

http://library.thinkquest.org/20991/alg2...

Answer 2

Basically, it's the fourth-root of all that is in the outer parentheses:

±4x^(7/4)y^(13/4)z^4

Answer 3

the rule is (a^b)^c = a^(b*c)

Sort of distribute 1/4 exponent over the  (256x^7)(y^13)(z^16)) expression yields (256x^7/4)(y^13/4)(z^16/4) now you do the rest ya lazy S**t.

Hope this helps,

Joe