I don't understand my homework, 8th grade algebra. Can someone please explain?

Question

Ok, there are different problems for some of these problems. I'll give you about two or three problems to hep me with. This is basically Order of Operations.

Evaluate:

4{5[13-2(6)]} -19.

Evaluate each expression:

157 - 29 + 23 X 9

I am SO confused. If you could help, that'd be great!

Answer 1

F.O.I.L.

First

Outside

Inside

Last

Answer 2

did you ever learn about P.E.M.D.A.S??

first you do the parentheis, then equotients, then mutlplying/dividing, then adding/subtracting

so for the first one, do parentheiss first,

since 6 is by itself, skip that, so i would be 13-2, which is 11. and then since those parenteihis are out of the way it would be

4{5x11(6)}-19

and tehn you multiply 5x11 which is 55. then multiply that by the 6, which is some big numer, then you multiply that by 4, and then subtract by 19.

the next one, you do 23x9, then 157 minus 29, and then add that to whatever 23x9 is.

Answer 3

OMG! thats what grade 8 work is like? AH!!!! im gonna do soooooooooo bad!

Answer 4

1.   4{5[13-2(6)]} - 19   multiply 2 times 6 first

4{5[13 -12]}-19    simplify the bracket

4{5[1]}-19   multiply 5 times 1

4{5} - 19   multiply 4 times 5

20 - 19   subtract



1

2.  157 -29+23 X 9   multiply first

157 -29 + 207  subtract

128 + 207

335

Answer 5

For the first, start from the inside-most of the parenthesis, so multiply the 2 by the 6 to get:

4{5[13 - 12]} - 19

Do the most inside again, 13 - 12:

4{5[1]} - 19

Again:

20 - 19 = 1

For the second one, multiplication and division come before addition and subtraction, so 23 X 9 first:

157 - 29 + 207 = 335

Answer 6

P.E.M.D.A.S.

parenthesis, exponents, multiplication, division, addition, and subtraction

do the problem in this order

so 4{5[13-2(6)]} - 19

2 x 6 = 12

4{5[13-12]} - 19

13-12 = 1

4{5[1]} - 19

5 x 1 = 5

4(5) -19

4 x 5 = 20

20 - 19 =

1

1 is your answer for the first one I believe.

and as for the second?

I THINK...

15 - 29 + 23 x 9

23 x 9 = 207

15 - 29 + 207

do that whole thing

and its 193

i think.......hope i helped

Answer 7

Start on the inside of the parentheses and work your way out, being sure to use your order of operations.

Top answer is 1 and bottom answer is 335

Answer 8

Order Of Operations

Parenthesis

ExponetsOrder Of Operations

Parenthesis

Exponets

Multiplication

Division

Addition

Subtraction

Evaluate:

4{5[13-2(6)]} -19.

First is Parentesis!

Evaluate:

4{5[13-12]} -19

4{5[1]} -19

4{5} -19

20 - 19

1

Your answer is 1

Evaluate each expression:

157 - 29 + 23 X 9

Due to the order of operations....you would multiply first so:

157 - 29 + 23 X 9

157 - 29 + 207

Then it is addition

157 - 236

Now subtraction

-79

Your answer is -79

Hope this was helpful!

Answer 9

Problem 1:

= 4(5[13 - 2{6}]) - 19

= 4(5[13 - 12]) - 19

= 4(5[1]) - 19

= 4(5) - 19

= 20 - 19

= 1

Answer: 1

Problem 2:

= 157 - 29 + (23 * 9)

= 128 + 207

= 335 OR

= 157 - (29 + [23 * 9])

= 157 - (29 + 207)

= 157 - (236)

= 157 - 236

= 79  OR

= (157 - 29 + 23) * 9

= 151 * 9

= 1,359 OR

= 157 - ([29 + 3] * 9)

= 157 - (32 * 9)

= 157 - 288

= 131

Answer 10

follow this rule:

Please Excuse My Dear Aunt Sally

P= parenthesis

e= exponents

M= multiplication

D= division

A= addition

S= Subtraction

that's the order that you evaluate the problem in.

use distributive property and multiply 6x2, which equals 12.

13-12=1

that's the parenthesis part.

use distributive property again and multiply 4 to 1, which is 4. 4-19= -15

i hope that helps.

Answer 11

the first answer is 1

4{5[13-2(6)]}-19

step by step:

1. multiply 2 and 6

so it would be 4{5[13-12]}-19

2. 13-12=1

so: 4{5[1]}-19

3. multiply 5 and 1

so: 4{5}-19

4. multiply 4 and 5

so: 20 - 19

5. 20 - 19 = 1

therefore your answer is 1

question two: (I'm supposing X is multipplication sincce its 8th grade you aren't working with letters yet)

157 - 29 + 23 X 9

answer is 335

step by step

1. multiply 23 and 9 ( always do multiplicatiion and divisoin before adding and subtracting)

so: 157 - 29 + 207

2. 157 minus 29

so: 128 + 207

3. add 128 and 207

so 128 + 207 = 335

I am 99.9% sure that this are correct. i am in alg II and passed all my other math classes with an a.

any more help feel free to email me

Answer 12

Please Remember My Dear Aunt Sally

Parenthesis, raising to the power, multiplication, division, addition, subtraction.

That is the order of operations.

Answer 13

4{5[13-2(6)]}-19

4{5[13-12]}-19

4{5[1]}-19

4{5}-19

20-19=1

157-29+23x9

157-29+207

128+207= 335

Answer 14

order of operations -- PEMDAS -- Parentheses, Exponents, Multiplication and Division, Addition and Subtraction

4{5[13-2(6)]}-19

(2(6) = 2*6)

= 4{5[13-12]}-19

= 4{5[1]}-19

= 4{5} - 19 = 4*5 - 19

= 20 - 19

= 1

157 - 29 + 23 * 9

Multiply 23*9 first, then do the subtraction and addition.

Answer 15

4{5[13-2(6)]}-19

4[5(13-12)]-19

4[5(1)]-19

4(5)-19

20-19

1

¯¯¯¯

157-29+[(23)(9]

157-29+207

335

¯¯¯¯

Answer 16

Order of operations are:

Brackets first (most inner one first)

Multiplication and Division

Addition and Subtraction.

You go from left to right if they're on the same level.

4{5[13-2(6)]} -19.

The inner most bracket is [13-2(6)].

This is 13 - 2 x 6.

You do multiplications first so 13 - 12 = 1.

So the expression simplifies to:

4{5[1]} - 19.

This is basically 4 x 5 x 1 - 19.

Which is 20 - 19 = 1.

157 - 29 + 23 X 9

Do multiplication first:

23 x 9 = 207

After that the expression is just left to right so:

157 - 29 + 207 = 335  

Answer 17

1) 1

2) 749

Answer 18

ugh i hated algebra 1 last year.

i got an A in the class. but i totally forgot everything i learned! GAH!

so sorry ];

Answer 19

For:   4{5[13-2(6)]} -19.

Start from the innermost part. That's 2(6)=12, right?

Then continue with [13-12]=1, right?

And so on.. (do it yourself!)

For: 157 - 29 + 23 X 9

I would start with 23x9.

Then it becomes easier from there..

Answer 20

No offense Im  like a 6th grader and i no the answer to that. like really this is so basic iv done problems way harder than this