I dunno how 2 do this? will you plz help me out?? thanks.-stephyy?

Question

Solve for x? 2 lil problems. help plz?

http://s218.photobucket.com/albums/cc35/stephanielazar1992/?action=view&current=untitled-11.jpg

Answer 1

To solve for x, you just need to ^3 both sides of the equation.  It's just like how you square something to undo a square root-- you cube something to undo a cubed root.  So you will end up with:

x = 12^3.

Do the same thing to find what the second one should be

Answer 2

Let √ be a cubed root.

Question #1:

Step 1: To eliminate the cubed root, raise both sides to the power of three. The cubed root and the exponent cancel out.

12 = √x

(12)ˆ3 = (√x)ˆ3

(12)ˆ3 = x

Step 2: Simplify

(12)ˆ3 = x

12 • 12 • 12 = x

1728 = x (<==ANSWER!!)

Question #2:

Step 1: To eliminate the cubed root, raise both sides to the power of three. The cubed root and the exponent cancel out.

15 = √x

(15)ˆ3 = (√x)ˆ3

(15)ˆ3 = x

Step 2: Simplify.

(15)ˆ3 = x

15 • 15 • 15 = x

3375 = x (<==ANSWER!!)

Hope I helped!

Answer 3

easier if you look at roots as exponents a cube root is to the (1/3) power how do you cancel (1/3) ... multiply by (3/1) in the exponent on both sides to get x= 12^3

2. same principle what is 15^3 (15 cubed)

Answer 4

1. 1728

2. 3375

Answer 5

All you have to do is cube both sides of the equation.

The answer is 12x12x12 or 15x15x15.

Cubing the square root will leave you with just x on one side and the answer on the other.

Answer 6

first problem x=12^3=1728

second problem x=15^3=3375

Answer 7

the first one is 4

the second is 5  

Answer 8

Just cube both sides of the equation to get rid of the third-root sign. So, for #41, you do 12 cubed which is 1728, and that is x. then you do the same thing for #42. 15 cubed, or 3375.

Answer 9

now now, no cheating! *try to find a calculator on google. that always helped me lol Good luck*