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I had asked a similar AP Chemistry question, but I forgot a vital part, Please HELP!!!!

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This is an AP Chemistry question that I have to do before the summer.

"The mass of beryillium that com bines with 1.000 g of oxygen to form bryllium oxide is 0.5633 g. When the atomic masses were first being measured, it was thought that the formula of beryllium oxide was Be<sub>2O<sub>3. What would be the atomic mass of beryllium if this were the case? Assume that oxygen has an atomic mass of 16.00."

This question is so hard for me because I have no clue of how to attack it. When you answer, please show or tell how you did it, so that I can learn from what you are doing.

I will award best answer to the person who gives the most correct and thorough answer.

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  1. let&#039;s find the moles of Oxygen atoms:

    1.000 g @ 16.00 g/mol = 0.0625 moles of oxygen

    let&#039;s use the ratio in Be2O3 to find the moles of Be:

    0.0625 mol Oxygen atoms @ 2 Be atoms / 3  Oxy atoms = 0.04167 moles Be

    let&#039;s find the mass per mole of Be:

    0.5633grams / 0.04167 moles = 13.52 g/mole

    your answer:the apparent atomic mass of Be is 13.52  

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