I had this question for homework:I am a 5 digit number i am read same forwards as backwards which makes me a?

Question

the other part:,y 3 digit is 5 more than my fith digit my fourth digit 3x more than my first digit the sum of my digit is fourteen what number am I?

Answer 1

palindrome

Answer 2

Lets call your 5 digit number as "abcde"

i.e. first digit is "a", second digit is "b", ...

Since the number is symetric (forward and backward are the same), then:

a=e

b=d

3rd digit = 5 more than 5th digit:

c = 5 + e

4th digit = 3 times first digit:

d = 3a

Sum of all digits = 14

a+b+c+d+e = 14

Since a=e and b=d, then subsititute for d and e in above equations:

c=5+a

b=3a

a+b+c+b+a = 2a+2b+c = 14

Substitute the values of c and b form the first two equations into the 3rd equation:

2a +2(3a) +(5+a) = 14

Solve for a gives:

a=1

Solve for other variables:

b=3a=3

c=5+a=6

Thus your number is:

13631