I have 200 L of glucose (C6H12O6) solution in a tank.....?

Question

Hi everyone, hopefully someone can help me with this:

I have 200 L of glucose (C6H12O6) solution in a tank. The concentration of sugar is 8 g/L. The density of the solution is 1010 kg/m3. Calculate the mass percentage of sugar in the tank.

Answer 1

(100%*0.008*200)/(1.01*200)

Answer 2

Mass solution = 0.200 m^3  x 1010 Kg/m^3 = 202 Kg => 202000 g

Mass glucose = 8 g/L x 200 L = 1600 g

% by mass = 1600 x 100 / 202000 =0.792

Answer 3

Sweet :)

Assuming 1000L=1m^3

8g/L*1000/1010=7.92g glucose/Kg solution

=0.792 % w/w