I have a 12" pipe that is 4' in length. How many gallons will this hold?

Question

The pipe is sch 80. Thanks to everyone for the help!

Answer 1

A standard 12" schedule 80 pipe has an O.D. of 12.75" and a wall thickness of 0.688", thus the I.D. is 11.374". The volume inside a 4ft x 12" schedule 80 pipe is:

V = pi(11.374)^2x48/4 = 4877.054026 in^3.

There are 231 in^3 per U..> gallon hence the pipe can hold 21.113 gal.

Answer 2

If you want an exact answer, you will need to give more detail about the pipe (material & schedule).  I'm also assuming you meant US gallons.

A rough answer is the cross sectional area x length.

Area = pi*r*r.  (3.14)(6")(6")=122.4 in^2

Length = 48"

Volume = (122.4)(48)=5,425.92 cubic inches.

And since 1 gallon (US) is 231 cubic inches,  5,425.92/231=23.5gal

Remember, this is a rough estimate.

Answer 3

Is 12" the ID? assuming so,

Volume in cubic ft is

V = πr²h

V = π(0.5)²4 = 3.14 cubic feet = 23.5 gallons

If the ID is 11" (radius = 0.458 ft)

then the number is 19.7 gallons

.

Answer 4

12" Sch 80 has an ID of 11.376 " and will hold 43.98 pounds of water per linear foot. A four foot length will contain 21.1 gallons of cold water.

Answer 5

Diameter of pipe = 0.3048m.

Length of pipe = 1.2192m.

Therefore volume = pi * D² * h / 4 = 0.08896m³

= 88.96 litres  (there are 1000L. in 1m³)

= 19.57 gallons  (there are 4.5461L. in 1 gallon).

Would have been much easier for you, if you just measured the thing in metres in the first place!

Answer 6

pi*r*r*l = vol

15.2cm * 122cm * pi = vol

88.5 liters = vol

88.5 liters * 1.056 quarts/liter= 93.5 quarts

23.4 gallons