I have a Brain Teaser Question! i need help.?

Question

THe pages in a large book are numbered starting with 1. How many pages are there if this requires 2989 digits.

I have tried to think but have NO clue. Maybe you guys do. Thanks!

Answer 1

The answer is 1024.

1-9 has 9 digits.

10-99 has 180 digits (90 numbers with 2 digits each.)

100-999 has 2700 digits (900 numbers with 3 digits each.)

1000-1024 has the remaining 100 digits.

9+180+2700+100=2989

Answer 2

The numbers 1-9 = 9 digits

10-99 = 178 digits

100-999 = 2697 digits

The answer I got was 1026 uses 2988 digits, and 1027 uses 2992 digits

Answer 3

This is a hard one -- I think I did it wrong but the answer is something like 1029 pages based on what I was trying to do.  If you assume that all of the pages between 1 and 9 have one digit, then all of the pages between10 and 99 have 2 digits, then all of the pages between 100 and 999 have three digits, and then the numbers go into 4-digit numbers, then you can multiply the number of numbers in each category by the number of digits required and add those up.  Unfortunately, when I did that, I got 168 digits required between 1 and 99 (I assume my counting error was in here somewhere, but don't have time to figure it out) , and then 2700 digits to number all of the pages between 100 and 999.  This came out to be 2868, so I subtracted taht from 2989 and got 121.  I assume an error of one digit somewhere because if it's 120 then you can just divide that by 4(the number of digits in each of the following pages) and get 30.  Adding 30 pages to page 999, I got 1029 pages as an answer.... Maybe I'm totally wrong but what a great big time-waster for me!  Thank you :)

Answer 4

there are 2990 you have to count the first pg

Answer 5

It says the pages are numbered, starting with 1 ( thats a digit). So, if they have 2989 digits. That'd be 2989 pages =)

Answer 6

1495

Answer 7

Um......2989 or 2988?? lol idk thats a guess.

Answer 8

1026.